7x^2-73x+136=0

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Solution for 7x^2-73x+136=0 equation:



7x^2-73x+136=0
a = 7; b = -73; c = +136;
Δ = b2-4ac
Δ = -732-4·7·136
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-73)-39}{2*7}=\frac{34}{14} =2+3/7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-73)+39}{2*7}=\frac{112}{14} =8 $

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